If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+3x-54.6=0
a = 1; b = 3; c = -54.6;
Δ = b2-4ac
Δ = 32-4·1·(-54.6)
Δ = 227.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{227.4}}{2*1}=\frac{-3-\sqrt{227.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{227.4}}{2*1}=\frac{-3+\sqrt{227.4}}{2} $
| -15+-2h=9 | | -16-4y=32 | | 30x2-5x=0 | | 1=2z−11 | | 9m=-90 | | -1.67=2.43(p+9)-1.67 | | 6(2)^x+1=30 | | -3(-g-10)+10=-10+8g | | -8t-3(7t+5)=-7(3t-7) | | (5r+5)=(8r-6) | | 10+8÷y=14 | | 2.x-7=3 | | 18+3x=-30+5x | | 2(j-5)-2=2 | | -38=8x+5 | | 0.9=0.4m | | 1.5(t-6)=3 | | -6=-3(m+6) | | 5=x=-22 | | 4(9u+10)-3u=-10+8u | | x(x)=x2=16x | | -4s+4=-6(-2s+10) | | –4s+4=–6(–2s+10) | | 2(p-2)-4=4 | | 0.72x=42 | | 11y-8y-11=35.08 | | 2(r−1)+2=10 | | -6(x-17)=-60 | | r+4r=3 | | 5=x=12 | | 6.x-16=2 | | X=-40y+200 |